Hi,

I'm currently building a website with 4 "sub" sites;

Content
Site1
Site2
Site3
Site4


Now i'm trying to create a navigation XSLT which onlu contains de Site (1-4).

Stupid as i am i didn't succeed, hopefully any here can help me.
I know the problem is in the for-each... but i jist cant get the "parent-sub-nodes".


The (stripped) XSLT i used ;

<blahblahblah>



<xsl:template match="/">
<ul class="menu">
<xsl:for-each select="$currentPage/parent::node">
<li class="menu">
<a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName"/> </a>
</li>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>


</blahblahblah>



Thanks for any clues...


gr. Walter

---

Walter E. Harms - level 2 certified
Chopin Software Development

“The journey of a thousand miles begins with a single step”.

Hi Dirk,

thanks for your reply. What you suggested is what i initialy thought however, only the subnodes of the current site are shown. I found the correct for-each...



Thanks for your help!


gr. Walter

---

Walter E. Harms - level 2 certified
Chopin Software Development

“The journey of a thousand miles begins with a single step”.